12x^2+64x-140=0

Solution for 12x^2+64x-140=0 equation:

12x^2+64x-140=0

a = 12; b = 64; c = -140;
Δ = b2-4ac
Δ = 642-4·12·(-140)
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-104}{2*12}=\frac{-168}{24}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+104}{2*12}=\frac{40}{24}
=1+2/3
$